Re: [sage-support] Function Field

2019-05-13 Thread Dima Pasechnik
this is also not working in 8.8.beta4: Does one need beta5? Or some ticket which is not yet in? On Mon, May 13, 2019 at 3:30 PM Santanu Sarkar wrote: > > Hi, > Sorry. This is not working: > > K. = FunctionField(GF(2)) > R. = K[] > f=y^2 + 1 + 1/x > L. = K.extension(f) > print L.places(1) > >

Re: [sage-support] Function Field

2019-05-13 Thread Santanu Sarkar
Hi, Sorry. This is not working: K. = FunctionField(GF(2)) R. = K[] f=y^2 + 1 + 1/x L. = K.extension(f) print L.places(1) I am using https://sagecell.sagemath.org/ On Mon, 13 May 2019 at 16:48, Vincent Delecroix <20100.delecr...@gmail.com> wrote: > Hello, > > It works for me and I obtain > >

Re: [sage-support] Function Field

2019-05-13 Thread Vincent Delecroix
Hello, It works for me and I obtain [Place (1/x, y), Place (1/x, y + 1), Place (x, x*y)] Could you describe the SageMath version you are using? Vincent Le 13/05/2019 à 10:10, Santanu Sarkar a écrit : Hi, This code works well. K. = FunctionField(GF(2)) R. = K[] f=y^2 + y + 1/x L. =

[sage-support] Function Field

2019-05-13 Thread Santanu Sarkar
Hi, This code works well. K. = FunctionField(GF(2)) R. = K[] f=y^2 + y + 1/x L. = K.extension(f) print L.places(1) But if I take f=y^2 + y + 1/x, it is giving error. -- You received this message because you are subscribed to the Google Groups "sage-support" group. To unsubscribe from this