Le dimanche 20 novembre 2022 à 19:16:44 UTC+1, gauri...@gmail.com a écrit :
> Thanks! I will ask on the Jupyter mailing list.
>
>>
>> Also is it possible for me to write [image: x^k-1] for various powers of
>> [image:
>> k] in latex in place of [image: x^k+2]. i.e. I want to write -1 wherever
You can also do `list(S)`, or depending on what you're doing it might be
better to iterate over its elements, as Emmanuel wrote: `for u in S...`
On Sunday, November 20, 2022 at 8:54:25 AM UTC-8 gauri...@gmail.com wrote:
> Oh wow! That was easy!
>
> Thanks so much!
> G
>
> On Sun, Nov 20,
Start with
g = SymmetricGroup(3)
chi = g.trivial_character()
u = g.subgroup([])
Next
reg = u.trivial_character().induct(g)
print(chi.scalar_product(reg))
yields as expected the answer 1.
Now repeat the very same two lines, but before doing so compute the
representatives of conjugacy classes
Thanks! I will ask on the Jupyter mailing list.
>
> Also is it possible for me to write [image: x^k-1] for various powers of
> [image:
> k] in latex in place of [image: x^k+2]. i.e. I want to write -1 wherever
> there is a 2 in the left column. Sure I can do this with print, but the
> output
Oh wow! That was easy!
Thanks so much!
G
On Sun, Nov 20, 2022 at 3:12 PM Emmanuel Charpentier <
emanuel.charpent...@gmail.com> wrote:
> No predefined method, but listing S’s elements seems easy :
>
> sage: R1.=GF(97)[]
> sage: p=lambda x:x^2+2
> sage: S=R1.quotient(p(t),'a')
> sage: L=[u for u
> How can I ask Sage to place each factorization in the right column on a
single line.
Both the display in a console and the LaTeX display given by `view` are
single-lined. I can reproduce your problem in Jupyter ; therefore, I think
that the question should be directed to a Jupyter-centered
No predefined method, but listing S’s elements seems easy :
sage: R1.=GF(97)[]
sage: p=lambda x:x^2+2
sage: S=R1.quotient(p(t),'a')
sage: L=[u for u in S]
sage: len(L)
9409
HTH,
Le dimanche 20 novembre 2022 à 07:39:27 UTC+1, gauri...@gmail.com a écrit :
> I am afraid I cannot seem to find
