I fully understand the query now. Thank you all :)
Simon Slavin 于2019年12月7日周六 下午1:23写道：
> On 7 Dec 2019, at 5:10am, Octopus ZHANG wrote:
>
> > I received no error from the execution. Could I know how to emit the
> error message if it is over length?
>
> There was no erro
Hi,
I received no error from the execution. Could I know how to emit the error
message if it is over length?
Richard Hipp 于2019年12月6日周五 下午9:24写道：
> On 12/6/19, Octopus ZHANG wrote:
> > Hi all,
> >
> >
> > I'm trying to fuzz sqlite, and I found the following query
Hi all,
I'm trying to fuzz sqlite, and I found the following query was executed for
more than one minute. (./sqlite3 < query.sql)
>> SELECT
printf('%*.*c',9||00600&66,1003)""WHERE""/"";
I also turned on the timer, but no time was printed. So I used `time` to
record:
ion like: 10 div 5 = 2.
>
>
> On 10.03.2020 08:21, Octopus ZHANG wrote:
> > Hi all,
> >
> >
> > I try to run a simple math expression, but SQLite gives no feedback :
> >
> > sqlite> select 99-(55/(30/57));
> >
> >
> >
> >
> &g
Hi all,
I try to run a simple math expression, but SQLite gives no feedback :
sqlite> select 99-(55/(30/57));
Should I expect it to return nothing?
Thank you
--
Yushan
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Thanks for the detailed explanation!
Keith Medcalf 于2020年3月10日周二 下午3:58写道：
>
> On Tuesday, 10 March, 2020 01:22, Octopus ZHANG
> wrote:
>
> >I try to run a simple math expression, but SQLite gives no feedback :
>
> >sqlite> select 99-(55/(30/57));
>
> &
I will use floating point as you all suggested. Thank you!
Simon Slavin 于2020年3月10日周二 下午3:25写道：
> On 10 Mar 2020, at 7:21am, Octopus ZHANG wrote:
>
> > sqlite> select 99-(55/(30/57));
> >
> > Should I expect it to return nothing?
>
> That's going in my list
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