Cassandra Simple Insert Statement using Spark SQL Fails with org.apache.spark.sql.catalyst.parser.ParseException

I'm trying to insert data into Cassandra table with Spark SQL as follows: String query = "CREATE TEMPORARY TABLE my_table USING org.apache.spark.sql.cassandra OPTIONS (table \"my_table\",keyspace \"my_keyspace\", pushdown \"true\")"; spark.sparkSession.sql(query);

Cassandra Simple Insert Statement using Spark SQL Fails with org.apache.spark.sql.catalyst.parser.ParseException

I'm trying to insert data into Cassandra table with Spark SQL as follows: String query = "CREATE TEMPORARY TABLE my_table USING org.apache.spark.sql.cassandra OPTIONS (table \"my_table\",keyspace \"my_keyspace\", pushdown \"true\")"; spark.sparkSession.sql(query);

Cassandra Simple Insert Statement using Spark SQL Fails with org.apache.spark.sql.catalyst.parser.ParseException

I'm trying to insert data into Cassandra table with Spark SQL as follows: String query = "CREATE TEMPORARY TABLE my_table USING org.apache.spark.sql.cassandra OPTIONS (table \"my_table\",keyspace \"my_keyspace\", pushdown \"true\")"; spark.sparkSession.sql(query);