...@spark.incubator.apache.org
Subject: Re: Key-Value decomposition
Hi,
But i've only one RDD. Hre is a more complete exemple :
my rdd is something like (A, 1;2;3), (B, 2;5;6), (C, 3;2;1)
And i expect to have the following result :
(A,1) , (A,2) , (A,3) , (B,2) , (B,5) , (B,6) , (C,3) ,
(C,2) , (C,1
Thank's
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Very straightforward:
You want to use cartesian.
If you have two RDDs - RDD_1(³A²) and RDD_2(1,2,3)
RDD_1.cartesian(RDD_2) will generate the cross product between the two
RDDs and you will have
RDD_3((³A²,1), (³B²,2), (³C², 3))
On 11/3/14, 11:38 AM, david david...@free.fr wrote:
Hi,
I'm a
Hi,
But i've only one RDD. Hre is a more complete exemple :
my rdd is something like (A, 1;2;3), (B, 2;5;6), (C, 3;2;1)
And i expect to have the following result :
(A,1) , (A,2) , (A,3) , (B,2) , (B,5) , (B,6) , (C,3) ,
(C,2) , (C,1)
Any idea about how can i achieve this ?
Thank's