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Can you please post how did you overcome this issue.
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Hi,
I think you can try
cast(l.timestamp as string)='2012-10-08 16:10:36.0'
Thanks,
Daoyuan
-Original Message-
From: whitebread [mailto:ale.panebia...@me.com]
Sent: Sunday, November 23, 2014 12:11 AM
To: u...@spark.incubator.apache.org
Subject: Re: SparkSQL Timestamp query failure
: SparkSQL Timestamp query failure
Thanks for your answer Akhil,
I have already tried that and the query actually doesn't fail but it doesn't
return anything either as it should.
Using single quotes I think it reads it as a string and not as a timestamp.
I don't know how to solve
” is the keyword of data type in
Hive/Spark SQL.)
From: Alessandro Panebianco [mailto:ale.panebia...@me.com]
Sent: Monday, November 24, 2014 11:12 AM
To: Wang, Daoyuan
Cc: u...@spark.incubator.apache.org
Subject: Re: SparkSQL Timestamp query failure
Hey Daoyuan,
following your suggestion I obtain
=19613i=1
Subject: Re: SparkSQL Timestamp query failure
Hey Daoyuan,
following your suggestion I obtain the same result as when I do:
where l.timestamp = '2012-10-08 16:10:36.0’
what happens using either your suggestion or simply using single quotes as I
just typed
-Timestamp-query-failure-tp19502.html
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,
Alessandro
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)
at org.apache.spark.deploy.SparkSubmit.main(SparkSubmit.scala)
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