I forgot about map :D That solution is more swifty than mine with String(format::).
-- Adrian Zubarev Sent with Airmail Am 8. Februar 2017 um 16:12:11, Tony Allevato via swift-evolution (swift-evolution@swift.org) schrieb: What you're asking for is already possible (avoiding the optional unwrap) by combining map() on Optional with ??: ``` let name1: String? = "name" print(name1.map { "\"\($0)\"" } ?? "null") // prints "\"name\"" let name2: String? = nil print(name2.map { "\"\($0)\"" } ?? "null") // prints "null" ``` So I guess the question is, does simplifying that rise to the level of wanting a custom operator? I personally don't think it does, but I could see an argument being made that an operator with defined semantics might be a small amount clearer than map + ??. But I think the benefits would have to be very strong, though. And as other folks have mentioned, having "!" in the operator name is somewhat misleading, since when I see that I expect a trap to occur in nil cases. On Wed, Feb 8, 2017 at 6:04 AM Maxim Veksler via swift-evolution <swift-evolution@swift.org> wrote: Hello, Let's assume I have an optional "name" parameter, based on the optional status of the parameters I would like to compose string with either the unwrapped value of name, or the string "null". The use case for is syntactic sugar to compose a GraphQL queries. A (sampled) illustration of the code that currently solves it looks as following: func query(name: String?) { let variables_name = name != nil ? "\"\(name!)\"" : "null" return "{ param: \(variables_name) }" } Based on optional status the following output is expected let name = "Max" query(name: name) // { param: "Max" } let name: String? = nil query(name: name) // { param: null } I think it might be useful to have an conditional unwrap operator !? that would enable syntax sugar uch as the following built into the language: func query(name: String?) { return "{ param: \(name !? "\"\(name)\"": "null") }" } This expression is expected to produce same output as the examples above. It means check the Optional state of name: String?, in case it has a value, unwrap it and make the unwrapped value accessible under the same name to the true condition part of the expression, otherwise return the false condition part of the expression. The effectively removes the need to have the "if != nil" and the forced unwrap syntactical code, and IMHO improves code readability and expressiveness. I'm wondering what the community thinks of the displayed use case, and proposed solution? -m _______________________________________________ swift-evolution mailing list swift-evolution@swift.org https://lists.swift.org/mailman/listinfo/swift-evolution _______________________________________________ swift-evolution mailing list swift-evolution@swift.org https://lists.swift.org/mailman/listinfo/swift-evolution
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