You could start with an anonymous function using the lambda operator, such as:
------------------------------------------------------------ mid_range = lambda x: x[len(x) // 2] Note: If you use len(x) / 2 in python 3.x you will get a TypeError because the division operator / returns a float. Floor // returns an int in 2.x and 3.x. Then use either: x = range(1000, 4001) mid_x = mid_range(x) # mid_x == 2500 or… mid_x = mid_range(range(500, 751)) # mid_x == 625 etc. to retrieve the middle element. You can extract the mid point of any sequence type, such as a string, using this function. mid_x = mid_range(‘12345678987654321’) # mid_x == ‘9’ ------------------------------------------------------------ middle_number = lambda lo, hi: abs(lo - hi) // 2 will work if you just need the mid point of two numbers; either ints or floats. mid_x = middle_number(0, 1000) # mid_x = 500 DW On Jul 27, 2011, at 8:16 PM, Alexander Quest wrote: > Does anyone know how to assign a certain numerical range to a variable, and > then choose the number that is the middle of that range? For example, I want > to assign the variable "X" a range between 1 and 50, and then I want to have > the middle of that range (25) return with some command when I call it > (perhaps rangemid or something like that?). In pseudocode, I am trying to say > X = range [1,50], return middle of range (which should return 25) but I don't > know how to code it. This is for a basic program I'm trying to write where > the player thinks of a number and the computer tries to guess the number in > as few tries as possible. Thanks for any help! > > -Alex > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
