These functions operate on an RDD of Double which is not what you have, so
no this is not a way to use DoubleRDDFunctions. See earlier in the thread
for canonical solutions.
On Sep 12, 2014 8:06 AM, "rzykov" <rzy...@gmail.com> wrote:
> Tried this:
>
> ordersRDD.join(ordersRDD).map{case((partnerid, itemid),((matchedida,
> pricea), (matchedidb, priceb))) => ((matchedida, matchedidb), (if(priceb >
> 0) (pricea/priceb).toDouble else 0.toDouble))}
> .groupByKey
> .values.stats
> .first
>
> Error:
> <console>:37: error: could not find implicit value for parameter num:
> Numeric[Iterable[Double]]
> .values.stats
>
>
>
>
>
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