OK I got it working with: z.map(row => (row.map(element => element.split("=")(0)) zip row.map(element => element.split("=")(1))).toMap)
But I'm guessing there is a more efficient way than to create two separate lists and then zip them together and then convert the result into a map. -- View this message in context: http://apache-spark-user-list.1001560.n3.nabble.com/Converting-Apache-log-string-into-map-using-delimiter-tp18641p18643.html Sent from the Apache Spark User List mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: user-unsubscr...@spark.apache.org For additional commands, e-mail: user-h...@spark.apache.org