the more scalable alternative is to do a join (or a variant like cogroup,
leftOuterJoin, subtractByKey etc. found in PairRDDFunctions)
the downside is this requires a shuffle of both your RDDs
On Thu, Feb 19, 2015 at 3:36 PM, Himanish Kushary <himan...@gmail.com>
wrote:
> Hi,
>
> I have two RDD's with csv data as below :
>
> RDD-1
>
> 101970_5854301840,fbcf5485-e696-4100-9468-a17ec7c5bb43,19229261643
> 101970_5854301839,fbaf5485-e696-4100-9468-a17ec7c5bb39,9229261645
> 101970_5854301839,fbbf5485-e696-4100-9468-a17ec7c5bb39,9229261647
> 101970_17038953,546853f9-cf07-4700-b202-00f21e7c56d8,791191603
> 101970_5854301840,fbcf5485-e696-4100-9468-a17ec7c5bb42,19229261643
> 101970_5851048323,218f5485-e58c-4200-a473-348ddb858578,290542385
> 101970_5854301839,fbcf5485-e696-4100-9468-a17ec7c5bb41,922926164
>
> RDD-2
>
> 101970_17038953,546853f9-cf07-4700-b202-00f21e7c56d9,7911160
> 101970_5851048323,218f5485-e58c-4200-a473-348ddb858578,2954238
> 101970_5854301839,fbaf5485-e696-4100-9468-a17ec7c5bb39,9226164
> 101970_5854301839,fbbf5485-e696-4100-9468-a17ec7c5bb39,92292164
> 101970_5854301839,fbcf5485-e696-4100-9468-a17ec7c5bb41,9226164
>
> 101970_5854301838,fbcf5485-e696-4100-9468-a17ec7c5bb40,929164
> 101970_5854301838,fbcf5485-e696-4100-9468-a17ec7c5bb39,26164
>
> I need to filter RDD-2 to include only those records where the first
> column value in RDD-2 matches any of the first column values in RDD-1
>
> Currently , I am broadcasting the first column values from RDD-1 as a list
> and then filtering RDD-2 based on that list.
>
> val rdd1broadcast = sc.broadcast(rdd1.map { uu => uu.split(",")(0)
> }.collect().toSet)
>
> val rdd2filtered = rdd2.filter{ h =>
> rdd1broadcast.value.contains(h.split(",")(0)) }
>
> This will result in data with first column "101970_5854301838" (last two
> records) to be filtered out from RDD-2.
>
> Is this is the best way to accomplish this ? I am worried that for large data
> volume , the broadcast step may become an issue. Appreciate any other
> suggestion.
>
> -----------
> Thanks
> Himanish
>
