Thanks Nan. I was searching for RowFactory.scala
Cheers On Mon, Apr 6, 2015 at 7:52 AM, Nan Zhu <zhunanmcg...@gmail.com> wrote: > Hi, Ted > > It’s here: > https://github.com/apache/spark/blob/61b427d4b1c4934bd70ed4da844b64f0e9a377aa/sql/catalyst/src/main/java/org/apache/spark/sql/RowFactory.java > > Best, > > -- > Nan Zhu > http://codingcat.me > > On Monday, April 6, 2015 at 10:44 AM, Ted Yu wrote: > > I searched code base but didn't find RowFactory class. > > Pardon me. > > On Mon, Apr 6, 2015 at 7:39 AM, Ted Yu <yuzhih...@gmail.com> wrote: > > From scaladoc > of sql/catalyst/src/main/scala/org/apache/spark/sql/Row.scala : > > * To create a new Row, use [[RowFactory.create()]] in Java or > [[Row.apply()]] in Scala. > * > > Cheers > > On Mon, Apr 6, 2015 at 7:23 AM, ARose <ashley.r...@telarix.com> wrote: > > I am trying to call Row.create(object[]) similarly to what's shown in this > programming guide > < > https://spark.apache.org/docs/latest/sql-programming-guide.html#programmatically-specifying-the-schema > > > , but the create() method is no longer recognized. I tried to look up the > documentation for the Row api, but it does not seem to exist: > > http://people.apache.org/~pwendell/spark-1.3.0-snapshot1-docs/api/scala/index.html#org.apache.spark.sql.api.java.Row > > Is there a new equivalent for doing this programmatic specification of > schema in 1.3.0? > > > > > -- > View this message in context: > http://apache-spark-user-list.1001560.n3.nabble.com/What-happened-to-the-Row-class-in-1-3-0-tp22389.html > Sent from the Apache Spark User List mailing list archive at Nabble.com. > > --------------------------------------------------------------------- > To unsubscribe, e-mail: user-unsubscr...@spark.apache.org > For additional commands, e-mail: user-h...@spark.apache.org > > > > >
