Hi Dan, You could zip the indices with the values if you like.
``` val sVec = sparseVector(1).asInstanceOf[ org.apache.spark.mllib.linalg.SparseVector] val map = sVec.indices.zip(sVec.values).toMap ``` Best, Burak On Tue, Jul 14, 2015 at 12:23 PM, Dan Dong <dongda...@gmail.com> wrote: > Hi, > I'm wondering how to access elements of a linalg.Vector, e.g: > sparseVector: Seq[org.apache.spark.mllib.linalg.Vector] = > List((3,[1,2],[1.0,2.0]), (3,[0,1,2],[3.0,4.0,5.0])) > > > scala> sparseVector(1) > res16: org.apache.spark.mllib.linalg.Vector = (3,[0,1,2],[3.0,4.0,5.0]) > > How to get the indices(0,1,2) and values(3.0,4.0,5.0) of e.g: > (3,[0,1,2],[3.0,4.0,5.0]) ? > It will be useful to map them into index->value pairs like: > 0->3.0 > 1->4.0 > 2->5.0 > > I could not find such info from: > > https://spark.apache.org/docs/1.2.0/api/scala/index.html#org.apache.spark.mllib.linalg.Vector > > Thanks. > > Cheers, > Dan > >
