You can't create a DataFrame from an arbitrary object since we don't know
how to figure out the schema. You can either create a JavaBean
<https://spark.apache.org/docs/latest/sql-programming-guide.html#programmatically-specifying-the-schema>
or manually create a row + specify the schema
<https://spark.apache.org/docs/latest/sql-programming-guide.html#programmatically-specifying-the-schema>
.
On Mon, Aug 10, 2015 at 11:22 AM, unk1102 <umesh.ka...@gmail.com> wrote:
> Hi I have my own Hadoop custom InputFormat which I want to use in
> DataFrame.
> How do we do that? I know I can use sc.hadoopFile(..) but then how do I
> convert it into DataFrame
>
> JavaPairRDD<Void,MyRecordWritable> myFormatAsPairRdd =
>
> jsc.hadoopFile("hdfs://tmp/data/myformat.xyz",MyInputFormat.class,Void.class,MyRecordWritable.class);
> JavaRDD<MyRecordWritable> myformatRdd = myFormatAsPairRdd.values();
> DataFrame myFormatAsDataframe = sqlContext.createDataFrame(myformatRdd,??);
>
> In above code what should I put in place of ?? I tried to put
> MyRecordWritable.class but it does not work as it is not schema it is
> Record
> Writable. Please guide.
>
>
>
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