are the credentials visible from each Worker node to all the Executor JVMs on
each Worker?
> On Dec 30, 2015, at 12:45 PM, KOSTIANTYN Kudriavtsev
> <kudryavtsev.konstan...@gmail.com> wrote:
>
> Dear Spark community,
>
> I faced the following issue with trying accessing data on S3a, my code is the
> following:
>
> val sparkConf = new SparkConf()
>
> val sc = new SparkContext(sparkConf)
> sc.hadoopConfiguration.set("fs.s3a.impl",
> "org.apache.hadoop.fs.s3a.S3AFileSystem")
> sc.hadoopConfiguration.set("fs.s3a.access.key", "---")
> sc.hadoopConfiguration.set("fs.s3a.secret.key", "---")
> val sqlContext = SQLContext.getOrCreate(sc)
> val df = sqlContext.read.parquet(...)
> df.count
>
> It results in the following exception and log messages:
> 15/12/30 17:00:32 DEBUG AWSCredentialsProviderChain: Unable to load
> credentials from BasicAWSCredentialsProvider: Access key or secret key is null
> 15/12/30 17:00:32 DEBUG EC2MetadataClient: Connecting to EC2 instance
> metadata service at URL:
> http://x.x.x.x/latest/meta-data/iam/security-credentials/
> 15/12/30 17:00:32 DEBUG AWSCredentialsProviderChain: Unable to load
> credentials from InstanceProfileCredentialsProvider: The requested metadata
> is not found at http://x.x.x.x/latest/meta-data/iam/security-credentials/
> 15/12/30 17:00:32 ERROR Executor: Exception in task 1.0 in stage 1.0 (TID 3)
> com.amazonaws.AmazonClientException: Unable to load AWS credentials from any
> provider in the chain
> at
> com.amazonaws.auth.AWSCredentialsProviderChain.getCredentials(AWSCredentialsProviderChain.java:117)
> at
> com.amazonaws.services.s3.AmazonS3Client.invoke(AmazonS3Client.java:3521)
> at
> com.amazonaws.services.s3.AmazonS3Client.headBucket(AmazonS3Client.java:1031)
> at
> com.amazonaws.services.s3.AmazonS3Client.doesBucketExist(AmazonS3Client.java:994)
> at
> org.apache.hadoop.fs.s3a.S3AFileSystem.initialize(S3AFileSystem.java:297)
>
> I run standalone spark 1.5.2 and using hadoop 2.7.1
>
> any ideas/workarounds?
>
> AWS credentials are correct for this bucket
>
> Thank you,
> Konstantin Kudryavtsev
