This is how you can do it in scala:
scala> val ts1 = from_unixtime($"ts", "yyyy-MM-dd")
ts1: org.apache.spark.sql.Column = fromunixtime(ts,yyyy-MM-dd)
scala> val finaldf = df.withColumn("ts1",ts1)
finaldf: org.apache.spark.sql.DataFrame = [client_id: string, ts: string,
ts1: string]
scala> finaldf.show
+--------------------+-------------+-----------+
| client_id| ts| ts1|
+--------------------+-------------+-----------+
|cd646551-fceb-416...|1477989416803|48805-08-14|
|3bc61951-0f49-43b...|1477983725292|48805-06-09|
|688acc61-753f-4a3...|1479899459947|48866-02-22|
|5ff1eb6c-14ec-471...|1479901374026|48866-03-16|
+--------------------+-------------+-----------+
The year is returning wrong here.May be the input timestamp is not correct
.Not sure.
Thanks
Deepak
On Mon, Dec 5, 2016 at 1:34 PM, Devi P.V <devip2...@gmail.com> wrote:
> Hi,
>
> Thanks for replying to my question.
> I am using scala
>
> On Mon, Dec 5, 2016 at 1:20 PM, Marco Mistroni <mmistr...@gmail.com>
> wrote:
>
>> Hi
>> In python you can use date time.fromtimestamp(......).str
>> ftime('%Y%m%d')........
>> Which spark API are you using?
>> Kr
>>
>> On 5 Dec 2016 7:38 am, "Devi P.V" <devip2...@gmail.com> wrote:
>>
>>> Hi all,
>>>
>>> I have a dataframe like following,
>>>
>>> +------------------------------------+---------------+
>>> |client_id |timestamp|
>>> +------------------------------------+---------------+
>>> |cd646551-fceb-4166-acbc-b9|1477989416803 |
>>> |3bc61951-0f49-43bf-9848-b2|1477983725292 |
>>> |688acc61-753f-4a33-a034-bc|1479899459947 |
>>> |5ff1eb6c-14ec-4716-9798-00|1479901374026 |
>>> +------------------------------------+---------------+
>>>
>>> I want to convert timestamp column into yyyy-MM-dd format.
>>> How to do this?
>>>
>>>
>>> Thanks
>>>
>>
>
--
Thanks
Deepak
www.bigdatabig.com
www.keosha.net
