Four minutes ago, Danny Yoo wrote:
> I'm trying to compare two paths for equality; I misread
> normalize-path and didn't realize that it does not do case folding,
> so that on Windows,
>
> (equal? (build-path "C:\\")
> (build-path "c:\\"))
>
> returns false. What's the right way to compare paths for equality?
IIRC, there was no right way -- I think that on windows you can have
some drives be case-sensitive and some are not.
> As a related question, what's the right way to see if one directory
> is a subdirectory of another?
Explode the two and check if one is a prefix of the other?
--
((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay:
http://barzilay.org/ Maze is Life!
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