-----Original Message----- From: pagnu...@htdconnect.com Subject: Electron assisted neutron exchange in solid state
Electron assisted neutron exchange process in solid state environment http://arxiv.org/pdf/1312.5498v1.pdf Excellent find, Lou. This Kalman neutron-exchange paper is most definitely of interest to LENR. It offers yet another hypothetical way to get nuclear energy out of hydrogen-loaded metals with no free neutrons (as with W-L)- and with few of the other indicia of hot reactions. This electron-assisted modality also seems to work well - even better - in the context of relativistic inner shell electrons in dense metals, which could possibly supply the energy deficit which is needed, instead of external electron irradiation (which needs only to provide for negative charge asymmetry). Relativistic electrons are evident in a few metals like nickel and palladium, which are out of place in the progression of the elements in the periodic table - in terms of density, compared to atomic weight - was a subject that was introduced recently. It has been given almost no attention in the literature, but it is standard physics. This could be another piece of the puzzle. Coincidentally, the paper in question focuses on exactly these two metals (but does not mention the inner shell electron velocity). Instead free electrons are accelerated slightly but they are slow and cannot supply the energy needed. Relativistic inner orbital electrons can provide the energy- so all one needs to complete the picture is electron substitution, which could involve the zero point field or possibly proton mediation of some kind. BTW - the density of nickel (or copper) is over 8900 kg/m3 whereas for comparison zinc, which has a higher atomic number - is 7130. Iron is 7974. The 25% density gain in nickel is due to tighter inner shell orbitals, which implies relativistic electrons. Zinc or iron have significantly less electron contribution to their structure compared to nickel and are more typical. Density alone is not enough, and the host metal must also be a proton conductor. But Kalman is saying that there is a double exchange, which seems to imply something remarkable and moreover falsifiable, and it should be subject to validation in a Rossi type of system. Jones
