I know counting sort can do in linear time but we dont need to use and extra space. as we do in case of counting sort.
I came up with this sol. but i think it's not stable so if u can find a stable algo plzzz.... i=0;j=n-1; while(i<j) { if(a[i]==a[j]) { if(a[i]==0) i++; else j--; //ie equal to 1 continue; //ie go to while (i<j) } if(a[i]<a[j]) i++; //ie a[i] has to be zero only else { //ie a[i] =1 and a[j] = 0 therefore swap them swap(a[i],a[j]); i++; j--; } } //end of while --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---