(A) Hull is _not_ a quadrilateral if the 4th point lies inside the triangle AND _many_ other points. For instance, extend the perpendicular bisector (just as a sample case) of any one side beyond the vertex of the triangle that it passes through.
The same triangle reasoning holds good here too right? If we choose the end points of the side that we are bisecting and the new point we are choosing on the perpendicular bisector as the triangle the other vertex will be inside the triange? I dont think i am getting the example correctly... (B) If we consider the plane as a unit square, then limiting assertions on the probability (like the one you made about three points being collinear) become less accurate Well this is not a real issue because even then the definition of a point is such that there are infinite points in a unit square so the assertion remains accurate --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
