If the array is sorted you can use binary search.
First divide the interval until you find an element for which array
[mid] == mid+1.

Then use binary search again:
the first number is left of mid
the second is right of mid

On Jul 29, 1:20 pm, Vijayasarathy K <vijaykan....@gmail.com> wrote:
> Consider an array of 'n' elements which contains all except 2 numbers
> from 1....(n + 2). How can we find the 2 missing elements?

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