if value in array is in something like millions.. then bit variable shud be having millions bits.... rite ??? means bits variable = pow(2,millions) rite... ?? result:- not possible..
for n=4 1,1000000000000000000000000,2,2 then think .. ?? On Mon, Aug 17, 2009 at 5:32 AM, Shyam <shyamheartbreak...@gmail.com> wrote: > > I think I could do it in O(n) . > > var bits=0 > var @array > > for each i in array > if (bits & i)!=0 > return i > else > bits=bits | i; > end if > end for > > I just use the pattern for powers of two > > let array be 2,4,2 > > so first > bits=0 i=2 so bits(000) & i(010) is 0 so bits= bits | i which is > bits=010 > next > bits=2 i=4 so bits(010) & i(100) is 0 so bits= bits | i which is > bits=110 > next > bits=6 i=2 so bits(110) & i(010) is 2 which is !=0 so we return i. > > I think that should be it. > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
