@manisha i think u didn't get my point every time it will return the different value ex values to be pushed 6,5,10,3,9,1 now push(a,b) a=element b=minimum value pushed till now (6,6) (6,6),(5,5) (6,6),(5,5),(10,5) (6,6),(5,5),(10,5),(3,3) (6,6),(5,5),(10,5),(3,3),(9,3) (6,6),(5,5),(10,5),(3,3),(9,3),(1,1)
now start popping (1,1) min in stack=1 (9,3) min in stack =3 similarly last (6,6) min in stack=6 so everytime u get min in O(1) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
