3 is min element then y to return 5??if  u remove 9,3
3 at tos 3 is min so y to remove 5 borther dave

On Thu, Oct 8, 2009 at 8:37 PM, Dave <dave_and_da...@juno.com> wrote:

>
> Satyam, let's work your example in detail. We've pushed your data onto
> the stack, and now we start popping.
>
> (6,6),(5,5),(10,5),(3,3),(9,3),(1,1), so remove the (1,1) and return
> 1.
> (6,6),(5,5),(10,5),(3,3),(9,3) so remove (3,3) and return 3.
> (6,6),(5,5),(10,5),(9,3). Now what? How do we find (5,5) to return 5?
>
> Dave
>
>
> On Oct 8, 6:15 am, harit agarwal <agarwalha...@gmail.com> wrote:
> > @manisha
> > i think u didn't get my point
> >
> > every time it will return the different value
> > ex
> > values to be pushed 6,5,10,3,9,1
> > now push(a,b) a=element b=minimum value pushed till now
> > (6,6)
> > (6,6),(5,5)
> > (6,6),(5,5),(10,5)
> > (6,6),(5,5),(10,5),(3,3)
> > (6,6),(5,5),(10,5),(3,3),(9,3)
> > (6,6),(5,5),(10,5),(3,3),(9,3),(1,1)
> >
> > now start popping
> > (1,1) min in stack=1
> > (9,3) min in stack =3
> > similarly
> > last (6,6) min in stack=6
> >
> > so everytime u get min in O(1)
> >
>

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