@meena
that is too specific example that you have taken.
such a BST2 can be inserted into BST1 in linear time any which way.

On Fri, Jan 29, 2010 at 5:10 AM, Ashish Meena <ashishmee...@gmail.com>wrote:

> Hi all,
>
> Lets say we do following steps to merge two BSTS's. Lets call them BST1 and
> BST2.
>
> 1. Check the value of root of BST2.
> 2. In BST1 find a place where root of BST2 can be put.
> 3. Remove the children from this place and store them as BST3 and BST4.
> 3. Attach BST2's root pointer at this place.
> We dont have to do anything more for BST2 as all children of BST2 are
> already at their proper place
> Now our BST1 has BST2 merged to it but it doesnt have BST3 and BST4.
> 4. Do inorder traversal of BST3 and BST4 and insert it to BST1.
>
> If we know the approximate size of BST1 and BST2 we can choose tree for our
> step 1 accordingly.
>
> This algorithm doesnt need any extra memory and can be almost O(n), if BST3
> and BST4 are very small trees.
>
> Does anybody see any issues with this approach?
>
>
> Regards,
> Ashish
>
>
> On Fri, Jan 29, 2010 at 2:52 PM, vivek bijlwan <viv...@gmail.com> wrote:
>
>> @ shingray ...  cartesian trees are not BSTs .  I guess nirmal's question
>> asks for a BST.
>> also cartesian trees have extra space requirements.
>>
>>
>> On Fri, Jan 29, 2010 at 12:07 AM, naga vinod kumar <
>> vinodkumark...@gmail.com> wrote:
>>
>>> hi varun ,it cant be in O(n) time ,it can be merged in O(nlogn) time.
>>>
>>>
>>> On Thu, Jan 28, 2010 at 10:37 PM, Varun S V <varun...@gmail.com> wrote:
>>>
>>>> Delete the nodes in the second BST in postorder. As and when you delete
>>>> this node, insert it into the first BST.
>>>>
>>>>
>>>>
>>>> On Thu, Jan 28, 2010 at 9:35 PM, Bijlwan <viv...@gmail.com> wrote:
>>>>
>>>>> hey nirmal  . i don't get that when you merge the two linked list ,
>>>>> how do you get the BST?
>>>>> making the BST would itself be a O(nlogn) process?
>>>>>
>>>>> On Jan 28, 5:03 am, Nirmal <nirm...@gmail.com> wrote:
>>>>> > Given two binary search trees, how to merge them in O(n) time and
>>>>> O(1)
>>>>> > space?
>>>>> >
>>>>> > It can be done using O(n) space as below,
>>>>> >
>>>>> > 1. covert BST #1 into linked list or sorted array
>>>>> > 2. covert BST #2 into linked list or sorted array
>>>>> > 3. merge them...
>>>>> >
>>>>> > but how to do this in place?
>>>>>
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>
>
> --
> Ashish Meena
>
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