for a particular query it will be O(log n+k).Where k is the no. of
elements to be reported.

On Wed, Mar 31, 2010 at 11:54 PM, BlackdiamonD <patidarc...@gmail.com> wrote:
> Binary Indexed Trees or Segment Interval trees.  building them also it will
> take O(n log(n))
> ..i feel for a particular query it will be difficult less than O(n) .because
> .u must know all the element.
>
> On Wed, Mar 31, 2010 at 8:26 PM, Priyanka Chatterjee <dona.1...@gmail.com>
> wrote:
>>
>> The list of N integers is not sorted.
>> The solution is asked for a particular query.
>>
>> @Abhijit Reddy: Can you elaborate more on Binary Indexed Trees or Segment
>> Interval trees. May be you opted for the correct data structure. Please
>> give the algorithm.
>>
>> @All: Doing a sorting for O(n logn) and then binary search for x1 and x2
>> in O(logn) will be less efficient than the simple solution of O(n). Think on
>> the data structure that can optimize it.
>> Is it possible in time complexity < O(n)?
>>>
>>
>>
>>
>> --
>> Thanks & Regards,
>> Priyanka Chatterjee
>> Third Year Undergraduate Student,
>> Computer Science & Engineering,
>> National Institute Of Technology,Durgapur
>> India
>> http://priyanka-nit.blogspot.com/
>>
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>
>
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