@anand:its similar to reference an array element using pointer...*(p+i)
which is imilar to &p[i] when u put *before & the value gets dereferenced
and hence p+i takes place same concept
On Sun, Jun 20, 2010 at 3:27 PM, anand <anandandymn...@gmail.com> wrote:
> it caculate the sum of two numbers.
>
> #include<stdio.h>
> int main()
> {
> int a=7,b=2,s;
> char *p;
> p=(char *)a;
> s= (int)&p[b]; //adding a & b //////HOW????
> printf("sum=%d\n",s);
> return 0;
>
> }
>
> can any one explain the code......??
>
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