Let me explain, supposing that you haven't really tried to understand
the code. The first logical product picks out bits 1, 3, 5, and 7 and
shifts them 1 position to the right. The second logical product picks
out bits 0, 2, 4, and 6 and shifts them 1 position to the left. Then
just or the two sets of bits together.

Dave

On Jun 21, 4:05 pm, Amit Jaspal <iit2007...@iiita.ac.in> wrote:
> @ Dave would u plz bother to discuss how do u arrive at this formula?
>
>
>
> On Mon, Jun 21, 2010 at 10:11 PM, Dave <dave_and_da...@juno.com> wrote:
> > Not hard at all:
>
> > y = ((x & 0xAA) >> 1) | ((x & 0x55) << 1)
>
> > Dave
>
> > On Jun 21, 7:07 am, amit <amitjaspal...@gmail.com> wrote:
> > > Given a byte, write a code to swap every two bits. [Using bit
> > > operators] Eg: Input: 10 01 11 01 Output: 01 10 11 10
>
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