can proceed like this...writing it quite fast, may have issues...
lets say T2 is being merged into T1
//assumption, trees have different data values
struct node * merge(struct node *pT1, struct node *pT2)
{
if (!pT2) return NULL;
struct node *ptemp=NULL;
if (pT2->data <pT1->data)
{
ptemp = pT2->right;
pT2->right =NULL;
pT1->left = merge(pT1->left, pT2);
pT1->right = merge(pT1, ptemp);
}
else {
ptemp = pT2->left;
pT2->left = NULL;
pT1->right= merge(pT1->right, pT2);
pT1->left= merge(pT1,ptemp);
}
}
On 7/26/10, Manjunath Manohar <manjunath.n...@gmail.com> wrote:
> @jalaj: could u pls elaborate on that a bit more..will it have the
> complexity of O(n logn logn), and also can u provide the pseudocode pls..
>
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Best Regards
Ashish Goel
"Think positive and find fuel in failure"
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