I am not sure, but can I do this using a suffix trie ? any comments ?


On Sun, Aug 1, 2010 at 2:29 PM, Ashish Goel <ashg...@gmail.com> wrote:

> solution could be to find the charcter position from both sides for each
> char of s2
> then from the 2*n array, find the smallest index from left and largest from
> right, within these two indexes all chars would be there
>
> one case where one of the chars can be missing can be found if a row in
> this 2-d array remains unmodified
>
>
>
> Best Regards
> Ashish Goel
> "Think positive and find fuel in failure"
> +919985813081
> +919966006652
>
>
>
> On Sat, Jul 31, 2010 at 10:22 PM, Nikhil Jindal <fundoon...@yahoo.co.in>wrote:
>
>> At the moment, I can only think of an O(n^3) algo.
>> Maybe if you can find a hash function which computes the hash value
>> depending on the unique characters the string contains, you can reduce it to
>> O(n^2).
>>
>>
>> On Sat, Jul 31, 2010 at 7:09 PM, srikanth sg <srikanthini...@gmail.com>wrote:
>>
>>> given two string , find the minimum  width in string 1 containing the
>>> all characters of string 2 , they may present in different order
>>> string 1-HELLO
>>> string 2- LE
>>> answer-2
>>>
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