plz .. if any one knows dp solution then tell ...

On Sun, Aug 1, 2010 at 7:31 AM, Ashim Kapoor <ashimkap...@gmail.com> wrote:

> I am not sure, but can I do this using a suffix trie ? any comments ?
>
>
>
>
> On Sun, Aug 1, 2010 at 2:29 PM, Ashish Goel <ashg...@gmail.com> wrote:
>
>> solution could be to find the charcter position from both sides for each
>> char of s2
>> then from the 2*n array, find the smallest index from left and largest
>> from right, within these two indexes all chars would be there
>>
>> one case where one of the chars can be missing can be found if a row in
>> this 2-d array remains unmodified
>>
>>
>>
>> Best Regards
>> Ashish Goel
>> "Think positive and find fuel in failure"
>> +919985813081
>> +919966006652
>>
>>
>>
>> On Sat, Jul 31, 2010 at 10:22 PM, Nikhil Jindal 
>> <fundoon...@yahoo.co.in>wrote:
>>
>>> At the moment, I can only think of an O(n^3) algo.
>>> Maybe if you can find a hash function which computes the hash value
>>> depending on the unique characters the string contains, you can reduce it to
>>> O(n^2).
>>>
>>>
>>> On Sat, Jul 31, 2010 at 7:09 PM, srikanth sg 
>>> <srikanthini...@gmail.com>wrote:
>>>
>>>> given two string , find the minimum  width in string 1 containing the
>>>> all characters of string 2 , they may present in different order
>>>> string 1-HELLO
>>>> string 2- LE
>>>> answer-2
>>>>
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