@srinivas the macro will replace the 'data' with 1 || 1 and this will make
the if condition true and print miracle.

On Sun, Aug 29, 2010 at 11:24 PM, srinivas reddy
<srinivaseev...@gmail.com>wrote:

> @aravind this is slight modification to your one and this is generalized
> one if it is not the way plz inform me
>
> #include<stdio.h>
> void main()
> {
> int m,n,p;
> printf("enter data");
> scanf("%d",&n);
> m=n||n;
> p=-n||-n;
> if(m==p && n!=0)
> printf("miracle");
> }
>
> here i replace data with m and -data with n so the code is working
> properlyy i think
>
>
>
> On Sun, Aug 29, 2010 at 11:04 PM, srinivas reddy <srinivaseev...@gmail.com
> > wrote:
>
>> @aravind i think u are right code plzz
>>
>>
>>
>> On Sun, Aug 29, 2010 at 10:59 PM, Aravind <aravind.aravin...@gmail.com>wrote:
>>
>>> #define int 1 ||
>>> #define data 1 || 1
>>>
>>> having theses macros will print miracle....
>>> if macros are allowed....
>>>
>>> On Sun, Aug 29, 2010 at 10:20 PM, Manjunath Manohar <
>>> manjunath.n...@gmail.com> wrote:
>>>
>>>> it will never print..and @ above..the != will never be evaluated
>>>> ..because of the short circuiting &&
>>>>
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