@srinivas i think miracle will not be printed....as n||n is n , so m==p is n
== -n and this is not possible.....
On Mon, Aug 30, 2010 at 12:00 AM, srinivas reddy
<srinivaseev...@gmail.com>wrote:
> @ aravind i wrote the code without macro isn't right plz check it..
>
>
> On Sun, Aug 29, 2010 at 11:56 PM, Aravind <aravind.aravin...@gmail.com>wrote:
>
>> @srinivas the macro will replace the 'data' with 1 || 1 and this will make
>> the if condition true and print miracle.
>>
>>
>> On Sun, Aug 29, 2010 at 11:24 PM, srinivas reddy <
>> srinivaseev...@gmail.com> wrote:
>>
>>> @aravind this is slight modification to your one and this is generalized
>>> one if it is not the way plz inform me
>>>
>>> #include<stdio.h>
>>> void main()
>>> {
>>> int m,n,p;
>>> printf("enter data");
>>> scanf("%d",&n);
>>> m=n||n;
>>> p=-n||-n;
>>> if(m==p && n!=0)
>>> printf("miracle");
>>> }
>>>
>>> here i replace data with m and -data with n so the code is working
>>> properlyy i think
>>>
>>>
>>>
>>> On Sun, Aug 29, 2010 at 11:04 PM, srinivas reddy <
>>> srinivaseev...@gmail.com> wrote:
>>>
>>>> @aravind i think u are right code plzz
>>>>
>>>>
>>>>
>>>> On Sun, Aug 29, 2010 at 10:59 PM, Aravind
>>>> <aravind.aravin...@gmail.com>wrote:
>>>>
>>>>> #define int 1 ||
>>>>> #define data 1 || 1
>>>>>
>>>>> having theses macros will print miracle....
>>>>> if macros are allowed....
>>>>>
>>>>> On Sun, Aug 29, 2010 at 10:20 PM, Manjunath Manohar <
>>>>> manjunath.n...@gmail.com> wrote:
>>>>>
>>>>>> it will never print..and @ above..the != will never be evaluated
>>>>>> ..because of the short circuiting &&
>>>>>>
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>>>>>
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