put all the numbers in a hash table( which demands O(n) space) and then pick
each number in the array and check in the hashtable whether x-chosen number
is present. this would take O(1) per search. Do it for all the numbers in
the array. It wold take O(n).

On Fri, Sep 10, 2010 at 11:00 PM, jagadish <jagadish1...@gmail.com> wrote:

> Hi,
> O(n) solution is possible if the array is presorted!
> Else i think it is NOT.
> 1.Have two ptrs (one from first and other to track the array from
> last)
> 2.s=a[left]+a[right]
> 3.if(s<sum) left++;
>  else if(s>sum) right--;
>  else
>  print "sum found"
>
> On Sep 10, 10:19 pm, bittu <shashank7andr...@gmail.com> wrote:
> > Q Given an array, find out if there exists a pair of nos. that adds up
> > to a sum 'x'
> >
> > in O(n) ???? possible,,
>
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