yes, but in O(n)?
How?
in O(n^2) its easy. For every int, if successive ints are lesser,
you've found a pair.

How can you find all pairs in o(n) time?

On Sep 13, 9:05 am, sharad kumar <aryansmit3...@gmail.com> wrote:
> linear decreasing sub sequence problem
>
> On Mon, Sep 13, 2010 at 9:10 PM, Raj N <rajn...@gmail.com> wrote:
> > Given an array of n integers find all the inversion pairs in O(n)
> > Inversion pair is one where a[i]>a[j], i<j
>
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