If we take high = MAX_CAPACITY

Here MAX_CAPACITY denotes the maximum no of words dictinary can index.
Actual no of words stored in dictionary could be less than MAX_CAPACITY.

On Wed, Sep 22, 2010 at 1:23 AM, Minotauraus <anike...@gmail.com> wrote:

> high= const.(10^const)
>
> What's const? The point of this isn't that it's a difficult prob to
> solve. Point lies in working with the design to make this close to log
> n.
>
> Define what value "const" holds.
>
> On Sep 21, 9:12 am, "coolfrog$" <dixit.coolfrog.div...@gmail.com>
> wrote:
> > its dictionary means shorted ordered arry.
> > let low = 1; and high= const.(10^const)
> >
> > Boolean isWord(String word)
> >    {  while(low <= high)
> >         {   mid = (low+ high)/2;
> >                 if(word = getWordAt(mid))
> >                   return true;
> >                if( word > getWordAt(mid))
> >                    {  high = mid-1
> >                    }
> >                 else
> >                      low = mid+1;
> >          }
> >
> >  }
> > Its a simple Binary Search Algorithm ...
> >    who's complexity is O(log n) times.
>
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-- 
Ramdas Kale
+919983526790

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