@Ashwath: Thanks for the correction.
Dave
On Sep 26, 1:20 am, aswath G B <aswat...@gmail.com> wrote:
> @Dave
>
> Slight change u have to do
>
> #include<stdio.h>
> main()
> {
> int a = 24;
> int b = (a | 7)+1; //This Line U have to change.....& not a || 7.....
> printf("%d",b);
> return 0;
>
> }
>
> tats it....
>
> btw it is nice one line easy soln...
>
>
>
>
>
> On Sat, Sep 25, 2010 at 10:17 PM, Dave <dave_and_da...@juno.com> wrote:
> > answer = (x || 7) + 1;
>
> > Dave
>
> > On Sep 25, 6:56 am, Krunal Modi <krunalam...@gmail.com> wrote:
> > > Q: Write an algorithm to compute the next multiple of 8 for a given
> > > positive integer using bitwise operators.
>
> > > Example,
> > > (a) For the number 12, the next multiple of 8 is 16.
> > > (b) For the number 16, the next multiple of 8 is 24.
> > > -------------------------
> > > I have written a code using bitwise operators...but, I am not happy
> > > with the solution....Is there any ONE LINE solution ?
> > > Here, is my code.
> > > Approach: shift left till LSB is 0 (say n number of times) then, OR
> > > with 1, finally shift right (same number of times).
>
> > > #include<stdio.h>
>
> > > int main(){
> > > int count,m,n,ans,t;
>
> > > printf("Enter any number :");
> > > scanf("%d",&n);
>
> > > m=8; //multiple of 8 !!
> > > ans=0;
> > > while(ans<=n){
> > > t = m;
> > > while(t){
> > > count=0;
> > > while(ans&1){
> > > count++;
> > > ans = ans>>1;
> > > }
> > > ans = ans|1;
> > > ans = ans<<count;
> > > t--;
> > > }
> > > }
>
> > > printf("[%d]\n",ans);
>
> > > return 0;
>
> > > }- Hide quoted text -
>
> > > - Show quoted text -
>
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> --http://aswath78.blogspot.com- Hide quoted text -
>
> - Show quoted text -
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