15
/ \
8 25
/ \
20 22
On Sep 26, 10:45 am, Chonku <cho...@gmail.com> wrote:
> This can also be done if we do an inorder traversal of the binary tree and
> look for the longest continuous sequence of numbers in ascending order.
Your idea will fail for above case.
In Order => 8 15 20 25 22
longest continuous sequence of numbers in ascending order => 8 15 20
25
But that's not the answer (I hope you realize what correct output
would be )
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