int denom(int Coin[],int n,int amount)
{
for(i=0;i<n;++i)
{
c=Coin[i];
for(j=c;j<=amount;++j)
{
den[j]+=d[j-c];
}
}
return den[amount];
}On Wed, Oct 6, 2010 at 4:43 AM, pre lak <pre.la...@gmail.com> wrote: > Hi all, > > Pls help me with the solution to the following problem related to the coin > changing problem. > > suppose that the available coins a ein the denominations c^0, c^1 , c^2... > c^k for some intgers c>1 and k>=1. show tht the greedy algorithm always > yeilds an optimal solution > > thanks in advance > Preethi > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algoge...@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com<algogeeks%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- yezhu malai vaasa venkataramana Govinda Govinda -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
