@Mahesh: Let's try this on 1, 2, 3, 4, 4. Then S = 14 and X_SUM = 0.
But the duplicate element is 4, not (14-0) / 2 = 7.

Dave

On Oct 20, 5:49 am, Mahesh_JNU <mahesh.jnumc...@gmail.com> wrote:
> Just add the number of the array and let the sum is S. Its complexity is
> O(n).
> Now XOR all elements of the array and say the result is X_SUM.Its complexity
> is  O(n).
> Now the duplicate element is = (S - X_SUM)/2
>
> On Wed, Oct 20, 2010 at 4:14 PM, Asquare <anshika.sp...@gmail.com> wrote:
> > @Anirvana - In context to the XOR method u suggested, could u plz
> > explain why does it so happen.. ??
>
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