there are (n*(n-1))/2pairs of points. I think if we use your method, the
time complexity should be O(n^4).

Is it possible to put all points into k different domain and using
T(n)=T(n/k)+f(n) to solve this problem?

On Sat, Oct 23, 2010 at 7:51 PM, preetika tyagi <preetikaty...@gmail.com>wrote:

> Is there any specific need to use recursion?
>
> One alternate is to find slope and constant (m and c) for every pair of
> points and same value of m & c will specify the points on the same line.
> Time complexity is O(n*n).
>
>
> On Sat, Oct 23, 2010 at 4:31 PM, Meng Yan <mengyan.fu...@gmail.com> wrote:
>
>> Given n point on the plane, find out whether any 3point on the same line.
>>
>> How to use recursion to solve the problem? Could you help me find the
>> algorithm and give the time complexity?
>>
>> Bests,
>> Claire
>>
>>
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