merge N/2 +1 times...

On Sat, Dec 4, 2010 at 7:48 AM, Gene <gene.ress...@gmail.com> wrote:

> This isn't quite right because you don't have to merge all the initial
> companies pairwise. I.e. you skip the case where A and B merge and
> then the result is merged with C.
>
> Rather, the answer is the number of binary trees with N leaves. (This
> does assume that all mergers involve only 2 companies.)  I'll let you
> look up how to compute these numbers.
>
> On Dec 3, 12:09 pm, Harshal <hc4...@gmail.com> wrote:
> > Nc2 * N-1c2 * N-2c2 * ..... * 2c2.
> >
> > where Nc2 means the number of combinations that can be made out of N
> numbers
> > taken 2 at a time. After merging any 2 companies, you will have N-1
> > companies left, and so on. If I interpreted the question correct, this is
> my
> > solution. Any more ideas?
> >
> > harsh
>
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yezhu malai vaasa venkataramana Govinda Govinda

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