@ Bittu:

Lets analyze your code with iterations:

the array contains  1 3 3 1 2 3 5 2 3
count contains       0 2 2 4 0 1 0 0 0

now 1st iteration:
i=8,7,6 the inner loop will nt be executed;

i=5; so j=0 only; as count[5]=1;
Now arr[pos](i.e array[0])=5

i=4; the inner loop fails

i=3; so j=0 to 3 as count[3]=4
Now array[1]=array[2]=array[3]=array[4]=3

i=2; so j=0 to 1 as count[2]=2
so array[5]=array[6]=2

and likewise array[7]=array[8]=1

so the final array 5 3 3 3 3 2 2 1 1

It doesnt match with the desired output.

Correct me if I m missing something.



On 12/15/10, bittu <shashank7andr...@gmail.com> wrote:
> @ankur,saurabh,soumya......
>
> ya ankur i forget to remove range from dare also no need to find
> range  for this..\
>
> put size-1 intead of range so that malloc will alocate the memory to
> all  elements in array ..no hope its fine...
>
>
> what i did is that
> i took counter array  thta cvontains the  no of times particular
> elements  comes
> then i have sort d array in reverse  order...&  prints accoding to
> count array..thats it... and the last line  of actual question says..
>
> """..in case of a tie  print the number which occurred first ""..i
> don't think d way i hav solved dis......
>
> still please let me no..if m wrong..
>
> Regards
> Shashank Mani Narayan " Don't b evil U can earn while u Learn"
> Computer Science & enginerring
> BIrla Institute of Technology,Mesra
> Cell 9166674831
>
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