Is it that the first case its a pointer to a pointer. So size of pointer to
a pointer is 4.
In next case , Its the size of array. So its 40. Is the explanation correct?
On Wed, Dec 15, 2010 at 9:43 AM, rahul <rahulr...@gmail.com> wrote:
> you would like to read peter ven der linden.(deep C secrets).
>
>
> On Tue, Dec 14, 2010 at 11:19 PM, Saurabh Koar
> <saurabhkoar...@gmail.com>wrote:
>
>> When u r passing an array to a function u only pass the base address
>> nt the total array...bt when sizeof is applied in main() u hv the
>> whole array. Thats why in the first case the output is 4(only one
>> address that is capable of holdin one integer)bt in the 2nd case the
>> output is 40(as u hv 10 addresses each capable of holding an integer).
>>
>> On 12/14/10, Divesh Dixit <dixit.coolfrog.div...@gmail.com> wrote:
>> > #define SIZE 10
>> > void size(int arr[SIZE])
>> > {
>> > printf("size of array is:%d\n",sizeof(arr));
>> > }
>> >
>> > int main()
>> > {
>> > int arr[SIZE];
>> > size(arr);
>> > return 0;
>> > }
>> >
>> > the out put should be 40 considering 4 byte integer...
>> >
>> > but out put is only 4... how this is possible...
>> > and again if we modify it
>> > #define SIZE 10
>> > int main()
>> > {
>> > int arr[SIZE];
>> > printf("size of array is:%d\n",sizeof(arr));
>> > return 0;
>> > }
>> > we are getting the desired output as 40 byte...
>> >
>> > thankyou in advance...
>> >
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