hahaha... lol... shoot in air ... lamo :-))


On Sat, Jan 1, 2011 at 6:28 PM, RAHUL KUJUR <kujurismonu2...@gmail.com>wrote:

> Suppose three gunmen are A, B, and C who have a probability of 100%, 50%
> and 33% respectively. The shooting will start from C, then B and at last A.
> Now there are several possibilities for C. If C shoots B, then A would
> shoot C with an accuracy of 100% or in other case if C shoots A, then B
> would shoot him with an accuracy of 50%. So he has a probability of getting
> killed. We can see in either of the cases C will die.
> So what C will do in first round is that it will fire the shot in air. Now
> the scenario gets interesting. By doing this C has turned the battle among
> three people into two people A and B. This will increase the chances of
> survival of C. So now its B's turn of firing. So he can fire at either A or
> C. If B fires at C, then A will shoot B with an accuracy of 100% and B knows
> that he will surely die so B won't do that. If B shoots A, then C will shoot
> B.
> I think this is the solution. Please point out if there are any loopholes.
>
>
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Thanks & Regards
Salil Joshi.
CSE MTech II, IITB
A-414, Hostel 12
+91.9819.442.865


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