Wow: Its a Running Contest :)

On Sun, Jan 2, 2011 at 11:07 PM, sanchit mittal <sm14it...@gmail.com> wrote:
> http://www.codechef.com/JAN11/problems/FLUSHOT/
> m getting wrong answer
> if there is any problem wid my algorythm do let me know
>
>> #include<stdio.h>
>>
>> int main()
>>
>> {
>>
>>     int t,D,N,j,i;
>>
>>     float T,*x,*y,*z,maxNo,minNo;
>>
>>     scanf("%d",&t);
>>
>>     while(t--)
>>
>>     {
>>
>>         scanf("%d %f",&N,&T);
>>
>>         x=(float*)malloc(sizeof(float)*(N+1));
>>
>>         y=(float*)malloc(sizeof(float)*(N+1));
>>
>>         z=(float*)malloc(sizeof(float)*(N+1));
>>
>>         for(i=0;i<N;i++)
>>
>>         {
>>
>>             scanf("%f",&x[i]);
>>
>>             }
>>
>>         if((x[1]+x[0])<=T || x[0]==0)
>>
>>         {
>>
>>             maxNo=x[0];
>>
>>             for(i=1;i<N;i++)
>>
>>             {  x[i]-=i*T;
>>
>>             if(x[i]<0)
>>
>>                x[i]=-x[i];
>>
>>             if(x[i]>maxNo)
>>
>>                maxNo=x[i];
>>
>>                       }
>>
>>
>>
>>             }
>>
>>         else
>>
>>         {    maxNo=0.0;
>>
>>              j=0;
>>
>>              for(i=0;i<N;i++)
>>
>>              {
>>
>>                  y[i]=x[i]-(x[0]+i*T);
>>
>>                  if(y[i]<0)
>>
>>                    { z[j]=-y[i];}
>>
>>                  if(y[i]>maxNo)
>>
>>                    { maxNo=y[i];}
>>
>>
>>
>>
>>
>>                  if(z[j]>minNo && j!=0 &&y[i]<0)
>>
>>                     { minNo=z[j];}
>>
>>                  if(y[i]<0)
>>
>>                     {j++;}
>>
>>                   if(j==1 &&y[i]<0)
>>
>>                     {minNo=z[0];}
>>
>>                     }
>>
>>
>>
>>                     if(N==2)
>>
>>                          maxNo=maxNo/2;
>>
>>                     else maxNo=(maxNo+minNo)/2;
>>
>>
>>
>>              }
>>
>>
>>
>>            printf("%.4f\n",maxNo);
>>
>>         }
>>
>>
>>
>>         return 0;
>>
>>     }
>
> --
> Sanchit Mittal
> Second Year Undergraduate
> Department of Computer Engineering
> Delhi College of Engineering
> ph- +919582414494
>
> --
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