Yeah you might be knowing how the expression evaluators work using stack
right. printf also uses the same approach....
On Sun, Jan 9, 2011 at 11:06 AM, priya mehta <priya.mehta...@gmail.com>wrote:
> @kartheek so does it use stack for that?
>
>
> On Sun, Jan 9, 2011 at 11:03 AM, priya mehta <priya.mehta...@gmail.com>wrote:
>
>> ok
>> i got that
>>
>> On Sun, Jan 9, 2011 at 11:01 AM, kartheek muthyala <
>> kartheek0...@gmail.com> wrote:
>>
>>> small correction printf evaluation starts from right to left.....
>>>
>>>
>>> On Sun, Jan 9, 2011 at 10:59 AM, kartheek muthyala <
>>> kartheek0...@gmail.com> wrote:
>>>
>>>> @priya,
>>>>
>>>> Generally printf evaluation starts from left to right....
>>>> so first a++ using post increments assign the value of 3rd %d to be 2
>>>> then a++gets evaluated , now a value is 3
>>>> 2nd %d takes a value as 3
>>>> 1st %d takes a value as 3
>>>>
>>>> if it is a preincrement like ++a in the third place
>>>> the output will be 3,3,3...
>>>>
>>>> got it i guess...
>>>>
>>>> Thanks,
>>>> Kartheek.
>>>>
>>>> On Sun, Jan 9, 2011 at 10:38 AM, priya mehta
>>>> <priya.mehta...@gmail.com>wrote:
>>>>
>>>>> int a=2;
>>>>> printf("%d %d %d",a,a,a++);
>>>>> the output is 3 3 2
>>>>> can someone tell the logic behind this?
>>>>>
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