call it by reference.
bst *rec = Null;
insert(rec,5);
void insert(bst *&rec,int data){rec->data = data;}
Or declare it as
void insert(bst **rec,int data){*rec->data = data;}
and invoke with insert(&rec,5);
First one is just syntactic sugar to me although you can argue about
the whole pass-by-value/ref/pointer thing for hours. :)
On Jan 27, 8:03 am, nishaanth <nishaant...@gmail.com> wrote:
> How can we pass pointers by value. Lets say even if it creates a copy of the
> pointer.
> The address stored by the pointer is the same. So when we dereference it
> shouldnt it get updated(as its just a memory address)?
>
>
>
> On Thu, Jan 27, 2011 at 5:39 PM, ritu <ritugarg.c...@gmail.com> wrote:
> > Here you are passing record pointer by value.
>
> > as you call insert(record, 5),stack frame of insert contains a copy
> > of record.after this value is modified by calling program,it should
> > be either returned explicitly to caller program or needs to be passed
> > by reference,so that calling program refers to it always by address.
>
> > On Jan 27, 4:17 pm, nishaanth <nishaant...@gmail.com> wrote:
> > > Hi guys,
>
> > > I have a small doubt regarding pointers and functions.
>
> > > Consider the following prototype
>
> > > void insert(bst * head, int data);
>
> > > This function creates a node and inserts the data in the node. Lets say i
> > > call this function iteratively from main.
>
> > > main(){
>
> > > bst* record=NULL;
> > > insert(record, 5);
> > > insert(record, 8);
>
> > > }
>
> > > I see that record is not getting modified. Now is this related to call by
> > > value. But since we are passing pointers shouldnt the change get
> > reflected
> > > in main.
> > > isnt is similar to passing an array?
> > > Enlighten me in this regard. I am tired of segfaults :(
>
> > > Regards,
> > > S.Nishaanth,
> > > Computer Science and engineering,
> > > IIT Madras.
>
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> --
> S.Nishaanth,
> Computer Science and engineering,
> IIT Madras.
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