C/C++ user : Take input in a char array or string(if using C++) : a
now do string addition. : a = a + a;
now do string substraction. : a = a - 2.

Java user : Use BigInt class

On Fri, Feb 4, 2011 at 8:12 PM, Logic King <crazy.logic.k...@gmail.com>wrote:

> please help me solve the problem on SPOJ
>
> https://www.spoj.pl/problems/BISHOPS/
>
>
> The logic of the problem is very easy i.e. 2*n-2
> but i am getting WA bcoz i am not able to deal with the large inputs.[?]
> plz help me how to get this AC.........
>
>
> #include<stdio.h>
> int main()
> {
>     long long int n,bmax;
>     while(scanf("%lld",&n)!=EOF)
>     {
>         if(n==1)
>         printf("%d\n",1);
>         else
>         {
>         bmax=(2*n)-2;
>         printf("%lld\n",bmax);
>
>         }
>     }
> return 0;
> }
>
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