hi Gunjan,

Can you please give the method....how you achieved this answer...


On Sat, Feb 26, 2011 at 9:36 PM, Gunjan Sharma <gunjan.khan...@gmail.com> wrote:
> As the competition is over I can reveal u the answer. There is only one
> number satisfying given condition and that is 578 so the answer is 20 :)
>
> On Fri, Feb 25, 2011 at 10:33 PM, vaibhav shukla <vaibhav200...@gmail.com>
> wrote:
>>
>> nothing to do with complexity...
>> just the ans
>>
>> On Fri, Feb 25, 2011 at 10:23 PM, Rel Guzman Apaza <rgap...@gmail.com>
>> wrote:
>>>
>>> Is there a maximum time complexity?
>>>
>>> 2011/2/25 vaibhav shukla <vaibhav200...@gmail.com>
>>>>
>>>> Find the sum of digits of all the numbers whose digits are all in
>>>> ascending order from left to right. All these numbers lie between 500 to
>>>> 1000 and satisfy M divides (M-1) ! + 1 , where M is any natural number.
>>>> ( " ! " denotes factorial of the number)
>>>> --
>>>>
>>>>
>>>>
>>>> best wishes!!
>>>> Vaibhav Shukla
>>>>     DU-MCA
>>>>
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>>>
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>>
>>
>>
>> --
>>   best wishes!!
>> Vaibhav Shukla
>>     DU-MCA
>>
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>
>
>
> --
> Regards
> Gunjan Sharma
> Chairman IEEE Students Chapter IIT Roorkee
> B.Tech IV year CSE
> Contact No- +91 9997767077
>
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-- 
Regards,
Mohan Mangal
Software Engineer, Bangalore
Mob- 80952-03670

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